Prove the following by contradiction: Proposition: Suppose \(n\) is an integer. If \(n\) is odd, then \(n^2\) is odd.
Consider the following proposition:
Proposition: For every \(n \in \mathbb{Z}, 4 \not\mid (n^2 + 2)\).
Set up the proof by contradiction. In other words, write the first line of the proof, beginning with “Suppose…”.
Complete the proof by contradiction of the proposition from #2.
Prove the following proposition: Proposition: Suppose \(a, b \in \mathbb{Z}\). If \(4 \mid (a^2 + b^2)\), then \(a\) and \(b\) are not both odd.
Definition: An integer \(n\) is even if \(n = 2a\) for some integer \(a \in \mathbb{Z}\).
Observation: by (confusing) convention, definitions are usually stated as a conditional but meant to imply a biconditional. That is, we interpret the above definition to mean: \[ n \text{ is even} \Leftrightarrow \exists a \in Z, n = 2a \] What is the distinction? We are saying that \(n\) is not even if it does not satisfy the given property, where the unidirectional implication would be inconclusive about that case.
Definition: An integer \(n\) is odd if \(n = 2a + 1\) for some integer \(a \in \mathbb{Z}\).
Definition: Suppose \(a\) and \(b\) are integers. We say that \(a\) divides \(b\), written \(a \mid b\), if \(b = ac\) for some \(c \in \mathbb{Z}\). In this case we also say that \(a\) is a divisor of \(b\), and that \(b\) is a multiple of \(a\).
Definition: Two integers have the same parity if they are both even or they are both odd. Otherwise they have opposite parity.
Definition/reminder: A real number \(x\) is rational if \(x = \frac{a}{b}\) for some integers \(a, b\). A number that is not rational is irrational.